Mysql update inner join sum




















Let us take a table from the database as a demo table to generate the total sum of column table values. To view the contents of this Books table let us query the data:. We are going to use the aggregate SUM function to fetch the total price of the books from the table quantity using the query below:. Here the result set is grouped by Supplier id and ordered by total cost calculated in descending order.

The result sum value is evaluated on the basis of a condition provided by the values in the next table. This is a guide to MySQL sum. Here we discuss an introduction to MySQL sum , syntax, parameters, how does it work with query examples.

This is another way whose syntax can be written as:. Also, the query is also filtered by the WHERE clause against certain specified conditions so that the rows of the table can be updated properly. We can also set multiple column values to update multiple table columns which can be parted by comma ,. For demonstration, let us create a database for a sample to use in the query which includes the tables to be applied for the MySQL Update Join.

Suppose, we have created two tables in the database:. The other table Merit is created having columns for student performances and percentage of merit. Now, under this database, we will design two tables as mentioned above Students and Merit which will be used for further Update Join query.

Using INNER join let us update the Salary column values in Students table based on the student performance and percentage calculation from Merit table using the succeeding query:. Explanation: Since the performance column is linking the two tables so, the Salary values are adjusted according to the percentage values respectively to new values as shown in the above output. We can set some percentage value to calculate the salary for new students like 1.

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Learn more. Update column based on sum of rows from another table by join Ask Question. Asked 5 years ago. Active 5 years ago. Viewed 4k times. Improve this question.



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